This question was previously asked in

DSSSB PRT General Section Official Paper - 14 Nov 2019 Shift 3

Option 1 : 2

**Given:**

The number is 547A

**Concept:**

The number which is divisible by 3 and 2 then number will be divisible by 6

The number is divisible by 3 when the sum of the individual digit is divisible by 3

The number which has 0, 2, 4, 6, or 8 at the unit place

**Calculation:**

⇒ 5 + 4 + 7 + A = 16 + A (Where only A = 2, 8 is possible)

⇒ 16 + 2 = 18 which is divisible by 6

⇒ 16 + 8 = 24 which is divisible by 6

⇒ The value of A = 2 and 8

**∴ The required result will be 2.**